12x^2(x/3+9x/x^2)=4x^3-72

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Solution for 12x^2(x/3+9x/x^2)=4x^3-72 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

12*x^2*(x/3+(9*x)/(x^2)) = 4*x^3-72 // - 4*x^3-72

12*x^2*(x/3+(9*x)/(x^2))-(4*x^3)+72 = 0

12*x^2*(x/3+(9*x)/(x^2))-4*x^3+72 = 0

12*x^2*(1/3*x+9*x^-1)-4*x^3+72 = 0

12*x^2*(1/3*x+9*x^-1)-4*x^3+72 = 0

108*x+72 = 0

108*x+72 = 0

108*x+72 = 0 // - 72

108*x = -72 // : 108

x = -72/108

x = -2/3

x = -2/3

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